ducati scrambler with bronco headlamp assembly
Posted: Fri Aug 11, 2023 12:12 pm
Good morning again-
As mentioned, the 1966 scrambler runs. I am working on the electrics now.
I have converted the ignition to battery, DC, using an ignition coil that seems to work. I have battery power to the headlamp assembly, which, as it turns out, is likely originally from a Bronco. There is a square diode thing inside, and a coil.
The wiring diagram for the bronco shows these two parts...
listing the coil-thing as a "single impedance" and the square diode as a rectifer.
If I read this diagram correctly, I will want to take AC power from one of the leads of the stator (just one, right?) and run that to the coil/single impedance, and then to the square rectifer... and then out of THAT I will get DC voltage, hopefully just more than 6 volts. Which could, conceivably, charge the battery. Correct?
Does it matter which of the two AC leads I tap into? As I recall, two of the leads produce AC power, and the other wire... does not. Likely a ground?
Am I on the correct path to getting DC electrons back into the battery?
I appreciate all of the archives of this forum, and also the "live" help of other list-readers! Thank you all!
Sincerely,
Bob Woolner
New Hampshire USA
As mentioned, the 1966 scrambler runs. I am working on the electrics now.
I have converted the ignition to battery, DC, using an ignition coil that seems to work. I have battery power to the headlamp assembly, which, as it turns out, is likely originally from a Bronco. There is a square diode thing inside, and a coil.
The wiring diagram for the bronco shows these two parts...
listing the coil-thing as a "single impedance" and the square diode as a rectifer.
If I read this diagram correctly, I will want to take AC power from one of the leads of the stator (just one, right?) and run that to the coil/single impedance, and then to the square rectifer... and then out of THAT I will get DC voltage, hopefully just more than 6 volts. Which could, conceivably, charge the battery. Correct?
Does it matter which of the two AC leads I tap into? As I recall, two of the leads produce AC power, and the other wire... does not. Likely a ground?
Am I on the correct path to getting DC electrons back into the battery?
I appreciate all of the archives of this forum, and also the "live" help of other list-readers! Thank you all!
Sincerely,
Bob Woolner
New Hampshire USA